So, last night we played haunt 68 "He Who must not be read" and I was the traitor. When we got to the point that the chest was located and opened, I realized that, the way the rules of the haunt was written, it was entirely possible that the heroes could win the haunt in one turn. From the traitor's tome:
So, when Flash opened the chest, we replaced the token, and then came the question: Can I try to kill the rabbit now?, because it was still Flash's turn and the rabbit hadn't moved yet. The rules say that a Hero may perform any number of rolls, as long as they are not for the same test. And the haunt continued very similar from this point. If he could kill the rabbit, it would turn into a duck, that Flash could kill again, and keep on doing tests until he destroys every Soulcrux (a very small chance, but possible)
We ended out house ruling it, that the moment an item changed, the turn of the hero ends, so the rabbit (then the duck, etc) takes the turn immediately. What do you guys think?
When the chest is opened: Inside is a rabbit that runs out. It now takes its turn in order after the hero who opened the Chest, and flees from the heroes as a monster with Speed 4. A hero may attempt a Speed roll of 3+ to kill it.
So, when Flash opened the chest, we replaced the token, and then came the question: Can I try to kill the rabbit now?, because it was still Flash's turn and the rabbit hadn't moved yet. The rules say that a Hero may perform any number of rolls, as long as they are not for the same test. And the haunt continued very similar from this point. If he could kill the rabbit, it would turn into a duck, that Flash could kill again, and keep on doing tests until he destroys every Soulcrux (a very small chance, but possible)
We ended out house ruling it, that the moment an item changed, the turn of the hero ends, so the rabbit (then the duck, etc) takes the turn immediately. What do you guys think?